3y 2 +5y−10=03, y, squared, plus, 5, y, minus, 10, equals, 0 what are the solutions to the equation above? choose 1 y=-\dfrac{5}{2}-\dfrac{\sqrt{145}}{ 2}

Step-by-step explanation:

Given the following quadratic equation:

You  need to use the Quadratic formula to find the solutions.

The Quadratic formula is:

In this case you can identify that:

The, substituting this values into the Quadratic formula, you get the following solutions for the given quadratic equation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b