The sum of two numbers is 66. two times the smaller number is 15 more than the larger number. what are the numbers?

Here is the set up:

Let x and y be the two numbers with x the smaller and y the larger number.

x + y = 66

2x = y + 15

We have two equations in two unknowns.

Take it from here.

27 and 39.

Step-by-step explanation:

Let x be the smaller number and y be the larger number.

It is given that sum of two numbers is 66.

       .... (1)

Two times the smaller number is 15 more than the larger number.  

        ... (2)

From (1) and (2) we get

Divide both sides by 3.

Substitute x=27 in equation (1).

Therefore, the numbers are 27 and 39.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3