4.2 task 2 (3.5 marks): process a low resolution sensor image with realistic features the first image was idealised for simplicity. the next image is more realistic and as such lens effects and other ambient disturbances including thermal gradient are present in the image. as such a more sophisticated algorithm of edge detection will be required. you are to use an algorithm that uses sobel edge detection (see appendix c) and implement it in the form of a matlab program that is capable of performing the following tasks: 1. (2 marks) find the centre of the circular feature in pixels. for this section, an edge threshold is required. initialise a threshold variable towards the top of your script and adjust to your own taste. a specific value will be provided by demonstrators when you are being marked. 2. (0.5 marks) calculate the radius of the feature in pixels. 3. (0.5 marks) calculate the area of the feature in pixels. 4. (0.5 marks) given that the distance from the camera to the surface is 1m and the camera sensor information from section 3, calculate the x-y coordinate of the centre in units of pixels, diagonal distance in meters relative to the top-left corner of the image (i. e.: pixel index 1,1), the radius of the feature in meters and the area of the feature in meters squared. the distance should be a variable declared in your matlab script and the camera specification are given in section 3.2. on demonstration day, a previously-unknown distance will be used for marking purposes. you may use matlab’s built-in implementation of the sobel algorithm (documentation: here) or implement it yourself.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w

"exterior angles = 360 / number of sides.

60 = 360 / sides

sides = 360 / 60

sides = 6"