Suppose a figure is located in quadrant i. which of the following sequences will result in an image that is located in quadrant ii?
a. rotate 360 degrees counterclockwise, then shift 1 unit up
b. rotate 180 degrees counterclockwise, then shift 1 unit down
c. rotate 90 degrees counterclockwise, then shift 1 unit up
d. rotate 270 degrees counterclockwise, then shift 1 unit down

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.