true or false
the codomain of a linear transformation is a subset of the range.
if t is a linear transformation and v ∈ range(t), then there is at least one u in the domain such that t(u) = v
if t(x) is not a linear transformation, then t(rx) 6= rt(x) for all r and x.
if a linear transformation t : r3 → r3 is one-to-one, then it must be onto as well.
if t is a linear transformation, then t(0) = 0.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

s

step-by-step explanation:

the answer is d on edge

step-by-step explanation:

the answer is 99.