Two rigid transformations are used to map triangle jkl to triangle mnq. the first is a translation of vertex l to vertex q. what is the second transformation? a reflection across the line containing lk a reflection across the line containing jk a rotation about point l a rotation about point k

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

49/6 is going to equal 8 1/6

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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if your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

max = c - (b2 / 4a).

the first step is to determine whether your equation gives a maximum or minimum.

-x2 + 4x - 2.     thats an example hope it