1. x2 + 12x + 27 = 0
what’s the answer ?

+ 3x +9x +27 = 0

x(x+3)+9(x+3)=0

(x+3)(x+9)=0

x=-3, x=-9

Step-by-step explanation:

a=1 b=12 c=27

sum=12

factor=27x 1

          3x9

also 3+9=12

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?