What are the minimum, first quartile, median, third quartile, and maximum of the data set? 60, 50, 130, 200, 180, 150, 100, 140. i think the answer is: minimum = 50 1st = 85 median = 135 3rd = 167.50 maximum = 200 however, none of the choices match my answer. what am i doing wrong?

Minimum = 50

First Quartile = 80

Median = 135

Third Quartile = 165

Maximum = 200

Step-by-step explanation:

First, it is important to reorder our values into ascending order:

50, 60, 100, 130, 140, 150, 180, 200

You've correctly identified the minimum, median and maximum values, however the quartiles are where the mistakes lie.

1. In order to calculate the first quartile, you need to look at where the median of the first half of the values is, ie. 50, 60, 100, 130

The median will be the value between (or the average of) 60 and 100:

(60 + 100)/2 = 80

Thus, the first quartile is 80.

2. In order to calculate the third quartile, we must find the median of the second half of the data set, ie. 140, 150, 180, 200

The median will be the value between (or the average of) 150 and 180:

(150 + 180)/2 = 165

Thus the third quartile is 165.

I find it's always a good idea to just draw this out and label the different values on paper to make it a bit easier.

Hope that helped! If you find anything confusing just ask :)

sorry, i'm new here and i'm just trying to figure this out. try quizlet. rate 5* you!

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length