The vertices of triangle pqr are p(-3, 8), q(-6, -4), and r(1, 1). if you reflect triangle pqr across the x-axis, what will be the coordinates of the vertices of the image?

The coordinates of the vertices of the image will be:

P'=(-3,-8)

Q'=(-6,4)

R'=(1,-1)

Step-by-step explanation:

If you reflect a point P=(x,y) across the x-axis, the coordinates of the image will be P'=(x,-y), then:

P=(-3,8)=(xp,yp)→xp=-3, yp=8→P'=(xp,-yp)→P'=(-3,-8)

Q=(-6,-4)=(xq,yq)→xq=-6, yq=-4→Q'=(xq,-yq)=(-6,-(-4))→Q'=(-6,4)

R=(1,1)=(xr,yr)→xr=1, yr=1→R'=(xr,-yr)→R'=(1,-1)

at least two

step-by-step explanation: