In a hydraulic jack, the pipe below the load has an area of 5 m2, and the pipe through which the input force transmits has an area of 1 m2. calculate the force required. kn of input force is necessary to balance a load of 10,000 n.

0.2kN

Step-by-step explanation:

An hydraulic jack works by the principle that pressure applied to one part in an enclosed liquid is transmitted equally in all parts of the liquid. this is in accordance with Pascal's principle.

Pressure= Force/Area

P=F/A

Pressure due to the load= Pressure due to input force for the system to be in balance.

Let force due to load be F₁, input force be F₂, Area at the load piston be A₁ and the area of the pipe through which the input force transmits be A₂, then,

F₁/A₁=F₂/A₂

10000N/5m²=F₂/1m²

F₂=(1000N×1m²)/5m²

F₂=200N

=0.2kN

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.