What is the solution to the equation below?

C  x=6

Step-by-step explanation:

sqrt(x+3) = x-3

Square each side

(sqrt(x+3))^2 = (x-3)^2

x+3 = (x-3)^2

x+3 = (x-3)(x-3)

FOIL

x+3 = x^2 -3x-3x+9

Combine like terms

x+3 = x^2 -6x+9

Subtract x from each side

x-x+3 = x^2 -6x-x +9

3 =  x^2 -7x +9

Subtract 3 from each side

3-3 =  x^2 -7x +9-3

0 = x^2 -7x+6

Factor

0 = (x-6)(x-1)

Using the zero product property

x-6=0   x-1 =0

x=6  x=1

Since we squared we need to check for extraneous solutions

x=1

sqrt(1+3) = 1-3

sqrt(4) = -2

2=-2

False

Extraneous

x=6

sqrt(6+3) = 6-3

sqrt(9) = 3

3=3

True   solutions

Option C.

Step-by-step explanation:

First, we need to square both sides of the equation:

We know that:

Then, applying this, we get:

Now we need to subtract "x" and 3 from both sides of the equation:

Adding like terms:

Factor the quadratic equation.  Find two numbers whose sum be -7 and whose product be 6. These numbers are: -1 and -6. Then:

Then:

Checking the first solution is correct:

Checking the second solution is correct:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

isn't it a pentagon? sense [3 (triangle) + 4 (rectangle)] - 2 (triangle and rectangle connected) = 5 (pentagon)