Acircular cake with a radius of 8 inches is cut from the center into 6 equal pieces. how many inches wide, to the nearest tenth of an inch, is the outer edge of each piece of cake?

8.4 inches.

Step-by-step explanation:

We know that the circumference of a circle can be calculated with this formula:

Where "r" is the radius of the circle.

We know that the circular cake (whose radius is 8 inches) is cut from the center into 6 equal pieces. Then, you need to divide the circumference of this circular cake by 6 to find the width of the outer edge of each piece of cake.

Therefore, this is (to the nearest tenth of an inch):

The width of the outer edge of each piece of cake  8.4 inches.

SOLUTION:

Given, a circular cake with a radius of 8 inches is cut from the center into 6 equal pieces. We have to find the width of the outer edge of each piece of cake.

We know that the circumference of a circle can be calculated with this formula: where "r" is the radius of the circle.

We know that the circular cake (whose radius is 8 inches) is cut from the center into 6 equal pieces.

Then, you need to divide the circumference of this circular cake by 6 to find the width of the outer edge of each piece of cake.

Therefore, this is (to the nearest tenth of an inch):

Hence, the cake piece is 8.4 inches wide.

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.