Find the area of a regular hexagon with a radius of 8 and an apothem of 4 squareroot 3. round your answer to the nearest tenth.

The area of the regular hexagon is 166.3 units^{2}  

Step-by-step explanation:

we know that

The area of a regular hexagon is equal to the area of six equilateral triangles

so

The area of a regular hexagon is

A=6[(1/2)bh]

The length side of the regular hexagon is equal to the radius

b=8 units

h=4\sqrt{3}  units > the apothem

substitute the values

A=6[(1/2)(8)(4\sqrt{3})]=166.3 units^{2}  

55? i think maybe

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3