Find three consecutive positive integers such that the product of the first and third interger is 17 more than 3 times the second interger

5, 6, 7

Step-by-step explanation:

In order to solve for the three integers, we can assign a variable and set up an equation:

first integer: x

second integer: x + 1

third integer: x + 2

Given that 'the product of the first and third integer is 17 more than 3 times the second integer':

x(x + 2) = 3(x + 1) + 17

Distribute: x² + 2x = 3x + 3 + 17

Combine like terms: x² - x - 20 = 0

Factor: (x - 5)(x + 4) = 0

Set them equal to '0' and solve:

x - 5 = 0      x + 4 = 0

x = 5               x = -4

Since the problem asks for positive integers, x must equal 5:

first = 5

second = 5 + 1 = 6

third = 5 + 2 = 7

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

step-by-step explanation: