Find the missing factor 5y^2-12y+7=(y-1) ( )

The correct answer is 5y-7

Step-by-step explanation:

Given that a quadratic expression is in the form ax²+bx+c where a,b and c are integers, we can factorize as follows

To factorize the expression 5y^2-12y+7, we need to find two numbers that when multiplied we get 5×7, that is ac, and that when added they give us -12 which is b,

these numbers are -7 and -5

therefore, 5y²-5y-7y+7 is our expression

Factorizing we get

             5y(y-1)-7(y₋1)

This gives  (y-1) (5y-7) as the factorized form of 5y²₋12y+7

Therefore the missing factor is 5y-7

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

pls ask