Need some pre-cal . will mark best answer as brainliest. 5 and 6 are also possible answers, they just didn’t fit in the photo.

Judging by the plot, the polynomial has 2 roots (at -1 and 2), so its degree is at least 2. But if it were 2, we'd expect a parabolic shape, but that's not the case here. In fact, the root at -1 has even multiplicity, which means the degree of the polynomial should be at least 3. But again, you're probably familiar enough with the shape of a cubic function to know that the degree would be higher than that, so at minimum, I think your answer of 4 is correct.

We can use the tools of calculus to verify this. We know of two extrema (a max at -1 and a min between 0 and 1) and one saddle point, which is enough to determine that there are at least 3 critical points, which means the derivative of the function is at least of degree 3, which would in turn mean the original function would have degree at least 4.

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step-by-step explanation:

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an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )