Abinary compound created by reaction of bismuth and an unknown element e contains 52.07% bi and 47.93% e by mass. if the formula of the compound is bi2e3, calculate the atomic mass of e.

Atomic mass of E is 128.24

Explanation:

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

            = (47.93 × 417.96 ) ÷ 52.07 %

            = 384.729

         E₃ = 384.729

Therefore; E = 384.729 ÷ 3

                     = 128.24  

The atomic mass of E is 128.24

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