Which is a point of the vertices for the following:

y≥3x−5
y≤−12x+2
x≥−4

a. (-4, -20)
b. (-4, -15)
c. (-4, -4)
d. (-4, 4)

i don't know you should ask someone who does

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204