Aquadratic function has a line of symmetry at x = –3 and a zero at 4.

q1: what is the distance from the given zero to the line of symmetry?

q2: what is the other zero of the quadratic function?

Part 1)

Part 2) The other zero is

Step-by-step explanation:

we know that

If the line of symmetry is equal to

then

the quadratic function is a vertical parabola and the x-coordinate of the vertex is

Part 1) What is the distance from the given zero to the line of symmetry?

The distance is equal to the absolute value of the difference of from

Part 2) What is the other zero of the quadratic function?

we know that

In a quadratic function the distance from the zero's to the line of symmetry is equal

so

Subtract from

The other zero is

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.