Mathematics, 29.06.2019 22:30 ngilliam1444

Answer $\frac{\sqrt[3]{9^{x-5} } }{27}\leq \frac{\sqrt{1} }{\sqrt{3x^{x+2} } }$

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Answer[tex]\frac{\sqrt[3]{9^{x-5} } }{27}\leq \frac{\sqrt{1} }{\sqrt{3x^{x+2} } }[/tex]...