How do yo solve a square root √90÷√40

You take out the squares inside of the radicals. you can do this by factoring each number. 90 is a multiple of 3x3x2x5 and 40 is 2x2x2x5. now you take out pairs. so its (3√2x5)/(2√2x5). then you cancel out the √2x5 and you're left with 3/2. :)

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.