What is the Interquartile Range (IQR) for the data set below? 48, 53, 44, 53, 57, 54, 55, 50, 34, 38, 52, 36, 37, 56, 38, 54, 47

because they could drop even lower..

if you was gonna solve for a, a is a   < -12

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0