Find the number of real solutions for the equation. x^2 - 3x +8 = 0

to determine the nature of the solutions use the discriminant

Given a quadratic equation in standard form : ax² + bx + c = 0

then the discriminant is b² - 4ac

• If b² - 4ac > 0 , then there are 2 real and distinct solutions

• If b² - 4ac = 0, there are 2 real and equal roots

• If b² - 4ac < 0 , there are no real solutions

for x² - 3x + 8 = 0 with a = 1, b= - 3 and c = 8

b² - 4ac = (- 3)² - (4 × 1 × 8 ) = 9 - 32 = - 23

Hence there are no real solutions to the equation

step-by-step explanation:

i need to answer questions so i dont know but i think its the first one because it goes up but a consent rate

the 3rd on is correct

step-by-step explanation: