Anyone have the answer to this? need asap?

For this case we have the following data:

Polynomial function of grade 5

Given roots: -2, 2,

Having an imaginary root given by , the other root, in the same imaginary way, must be given by its complex conjugate, that is, .

In this way, the fourth root is given by:

Since the polynomial function is grade 5, it must have 5 roots. Thus, the fifth root must be given by a real number.

Thus, the roots of the polynomial function are given by: three real roots and two imaginary roots.

Option D

f(x) has 3 real roots x = -2, x = 2 and x = 4

complex roots occur in conjugate pairs

x = i is a root then x = - i is a root

there are therefore 2 imaginary roots

f(x) has 3 real roots and 2 imaginary roots

answer: 12   they all have at least 28 days

step-by-step explanation: haha

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.