Agolfer hits a golf ball with a velocity of 36.0 meters/second at an angle of28.0°. if the hang time of the golf ball is 3.44 seconds, what is the range ofthe golf ball?

The range of a projectile is the maximum horizontal distance between the point of origin to the end point. It can be calculated through the equation,

range = v²sin2θ/g

where v is the initial velocity, θ is the angle, and g is the gravitational constant.

Substituting the known values,

range = (36 m/s)² x (sin2(28°)) / 9.8 m/s²

range = 109.64 m

Thus, the range of the golf ball is approximately 109.64 m.

Hope this helps!

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225