The angle a is acute and sec a=k. find in terms of k the value of cosec a. can u guys put in the process ?

Fundamentally you can get there using the identity

... sin(a)² + cos(a)² = 1

... 1/cosec(a)² + 1/k² = 1 . . . . . substituting for sec(a) and sin(a)

... 1/cosec(a)² = 1 - 1/k² = (k² -1)/k² . . . . subtract 1/k²

... cosec(a)² = k²/(k² -1) . . . . . Multiply by cosec(a)²k²/(k²-1)

... cosec(a) = k/√(k²-1) . . . . . .take the square root

You can get there slightly faster using the identities tan²=sec²-1; csc=sec/tan.

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )