X= y 2 - 1 2x - y = 4 which of the following equations could be the result of using substitution to solve the system? a. 2y 2 - y - 5 = 0 b. 2y 2 - y - 6 = 0 c. 2y 2 - 2y - 5 = 0

Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
I hope this helps!