Find the missing side lengths leave answers as radicals in simplest from

15) tan 45° = opposite leg / adjacent legtan 45°=3sqrt(2)/y→1=3sqrt(2)/y→y=3sqrt(2)using pythagoras theorem: x=sqrt[(3sqrt(2))^2+(3sqrt(2))^2]x=sqrt[2(3)^2(sqr(2))^2]x=sqrt[2(9)(2)]x=sqrt(36)x=6answers: y=3sqrt(2), x=616) sin30°=opposite leg / hypotenusesin30°=n/61/2=n/66(1/2)=n6/2=n3=nn=3using pythagoras teorem: m=sqrt(6^2-n^2)m=sqrt(6^2-3^2)m=sqrt(36-9)m=sqrt(27)m=sqrt(9*3)m=sqrt(9)sqrt(3)m=3sqrt(3)answers: m=3sqrt(3), n=  3