G={(-9,,,-,-5)}h(x)=3x-4find the followingg^-1(-6)=h^-1(x)=(h^-1·h)( 3)=

A) The ordered pair with -6 as the dependent value is (2, -6).
  g^-1(-6) = 2

b) Swap x and y and solve for y.
  x = 3y -4
  x +4 = 3y
  (x +4)/3 = y
Then the inverse function can be written as
  h^-1(x) = (x +4)/3

c) You have shown the product of h^-1(x) and h(x). We have to assume that is what you intend.
  h^-1(3) = (3 +4)/3 = 7/3
  h(3) = 3×3 -4 = 5
  (h^-1·h)(3) = h^-1(3)·h(3) = (7/3)·5
  (h^-1·h)(3) = 35/3

If you intend (h^-1◦h)(3), that value is 3.