How to design a gray code converter to drive a seven-segment indicator. The 4 inputs to the converter circuit(A, B,C and D) represent a decimal digit coded using the gray code. Assume that only input combinations representing the digits 0 through 9 can occur as inputs, so that the six unused combinations are dont-care terms

explanation:

hello, nice to meet you if you know the answer, what am i saying?

answer:

the correct answer is d

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)