Part A. Write a method countOfLongest that accepts an array of Strings as a parameter and returns the count (int) of elements in that array with length equal to the longest String in that array. See two examples above. Part B. Write a method countOfLongest that accepts an array of int's as a parameter and returns the count (int) of elements in that array with number of digits equal to the largest int in that array. See two examples above.

The methods are as follows:

public static int countOfLongest(String [] myarray){

    int strlen = 0, kount = 0;

    for(int i = 0; i<myarray.length;i++){

        if(myarray[i].length() > strlen){

            strlen = myarray[i].length();         }     }

    for(int i = 0; i<myarray.length;i++){

        if(myarray[i].length() == strlen){

            kount++;         }     }

    return kount;}

public static int countOfLongest(int [] myarray){

    int diglen = 0, kount = 0;

    for(int i = 0; i<myarray.length;i++){

    int lengt = String.valueOf(myarray[i]).length();

        if(lengt > diglen){

            diglen = lengt;         }     }

    for(int i = 0; i<myarray.length;i++){

        int lengt = String.valueOf(myarray[i]).length();

        if(lengt == diglen){

            kount++;         }     }

    return kount;}

Explanation:

This defines the countOfLongest of the string array

public static int countOfLongest(String [] myarray){

This initializes the length of each string and the kount of strings with that length to 0

    int strlen = 0, kount = 0;

This iterates through the array

    for(int i = 0; i<myarray.length;i++){

The following if condition determines the longest string

        if(myarray[i].length() > strlen){

            strlen = myarray[i].length();         }     }

This iterates through the array, again

    for(int i = 0; i<myarray.length;i++){

The following if condition checks for the count of strings with the longest length

        if(myarray[i].length() == strlen){

            kount++;         }     }

This returns the calculated kount

    return kount;}

This defines the countOfLongest of the string array

public static int countOfLongest(int [] myarray){

This initializes the length of each integer and the kount of integer with that length to 0

    int diglen = 0, kount = 0;

This iterates through the array

    for(int i = 0; i<myarray.length;i++){

The calculates the length of each integer

    int lengt = String.valueOf(myarray[i]).length();

The following if condition determines the longest integer

        if(lengt > diglen){

            diglen = lengt;         }     }

This iterates through the array, again

    for(int i = 0; i<myarray.length;i++){

The calculates the length of each integer

        int lengt = String.valueOf(myarray[i]).length();

The following if condition checks for the count of integer with the longest length

        if(lengt == diglen){

            kount++;         }     }

This returns the calculated kount

    return kount;}

See attachment for complete program which includes main

answer; code of ethicsi believe is the correct answer;