What does the following loop do? val = 0
total = 0

while (val < 10):
val = val + 1
total = total + val
print(total)

Prints the numbers backwards from 10 to 1.

Prints the sum of the numbers from 1 to 10.

Finds the average of the numbers between 1 and 10.

Prints the numbers from 1 to 10.

The editing of digital photos us about the same level of difficulty as editing an analog photo

4. a1. vince owns a television repair shop that is insured undera commercial package policy. the policy includes thebuilding and personal property coverage form and thecauses-of-loss broad form. the declarations page indicatesthat coverage applies to both the building and the namedinsured's business property. explain whether or not thefollowing losses would be covered under his policy. a. a fire occurs on the premises, and the building isbadly damaged. b. a burglar steals some money and securities from anunlocked safe. c. a business computer is damaged by vandals whobreak into the shop after business hours. d. a tornado touches down near the store. several tel-evision sets of customers in the shop for repair aredamaged in the storm. til

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }