Give the 16-bit 2's complement form of the following 8-bit 2's complement numbers: (a) OX94 (b) OXFF (c) OX23 (d) OXBCWhich of the following 16-bit 2's complement numbers can be shortened to 8 bits and maintain their values?(a) OX00BA(b) OXFF94(c) OX0024(d) OXFF3C

Answer is provided in the explanation section

Explanation:

Convert 8-bit 2’s complement form into 16-bit 2’s complement form.

First write value in binary then check for 8 th bit value. If it is positive the upper 8 bits will  be zero otherwise will be 1s.

8-bit number   Binary of number    Insert 8 bits                  16-bit number

0X94                1001-0100                 1111-1111-1001-0100            0XFF94

0XFF                1111-1111                       1111-1111-1111-1111                 0X

0X23                0010-0011                 0000-0000-0010-0011    0X0023

0XBC               1011-1100                    1111-1111-1011-1100              0XFFBC

Which of the following 16-bit 2’s complement form can be shortened to 8-bits?

16-bit number        8-bit number

0X00BA                  0XBA

0XFF94                   MSB bits are not zero so we can’t  truncate it to 8-bit No

0X0024                  0X24

0XFF3C                   MSB bits are not zero so we can’t  truncate it to 8-bit No

false as there is no connection between those two industries