Given the recursive algorithm foo(n) below, write a recurrence, t(n), for its running time.
foo(n) {
total = 0
if n = 1 return 2
else {
total = foo(n/4) + foo(n/4)
for i = 1 to n do
for k = 1 to 3 do
total = total + k
return total }
}

False if not look it up online

This printout will be      akes======in java, somestring.substring(a,b) will return a portion of somestring, including index a and up to but not including index b.in java, string indexes start from 0. the very first character has an index of 0.for  shakespeare, we have    "shakespeare".substring(2,6); gets us "akes"

Write it yourself you lazy "coder"!

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