Hey guys, I really need help with algebra... Solve the system by substitution.
x= −8y
−x+y= 18
=(_,_)

(-16,2)

Step-by-step explanation:

x= −8y

−x+y= 18

substitute for x:

-(-8y) + y = 18

8y + y = 18

9y = 18

divide both sides by 9:

y = 2

x = -8(2) = -16

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

a

step-by-step explanation: