At a particular temperature, 12.0 moles of so3 is placed into a 3.0-l rigid container, and the so3 dissociates by the reaction 2so3(g) 34 2so2(g) 1 o2(g) at equilibrium, 3.0 moles of so2 is present. calculate k for this reaction.

The value of k for the reaction is 0.055.

In the reaction, the dissociate to form and .

2 moles of sulfur trioxide will form 2 moles of sulfur dioxide and 1 mole of oxygen.

According to the ICE setup :

4                  0           0     I

-2x               +2x        x     C

                     1                  E

Since there were 3 moles of   at the equilibrium.

2x = 3 moles.

x = 1.5 moles.

The initial amount of = 12 moles

At equilibrium, there has been a 2x reduction.

The amount of   = 12 - 2x

= 12 - 3

= 9 moles.

The amount of at equilibrium is 2x

= 3 moles.

The amount of at equilibrium is x.

= 1.5 moles.

k can be calculated as:

k =

k = 0.055.

The value of k for the reaction is 0.055.

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first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j