Chemistry, 01.08.2019 01:30 little68941

At a particular temperature, 12.0 moles of so3 is placed into a 3.0-l rigid container, and the so3 dissociates by the reaction 2so3(g) 34 2so2(g) 1 o2(g) at equilibrium, 3.0 moles of so2 is present. calculate k for this reaction.

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2 SO₃ --> 2 SO₂ + O₂
I 12 0 0
C -2x +2x +x

E 12-2x 2x x

Since the moles of SO₂ at equilibrium is 3 mol, 2x = 3. Then, x = 1.5 mol. So, the amounts at equilibrium is:
SO₃: 12 - 2(1.5) = 9
SO₂: 2(1.5) = 3
O₂: 1.5

The formula for K basing on the stoichiometric reaction is:
K = [SO₂]²[O₂]/[SO₃]²
where the unit used is conc in mol/L.

K = [3 mol/3 L]²[1.5 mol/3 L]/[9 mol/3 L]²
K = 0.0556

Answer from: mydoggy152

The value of k for the reaction is 0.055.

In the reaction, the $\rm SO_3$ dissociate to form $\rm SO_2$ and $\rm O_2$ .

2 moles of sulfur trioxide will form 2 moles of sulfur dioxide and 1 mole of oxygen.

According to the ICE setup :

$\rm 2\; SO_3\;\rightarrow\;2\;SO_2\;+\;O_2$

4 0 0 I

-2x +2x x C

1 E

Since there were 3 moles of $\rm SO_2$ at the equilibrium.

2x = 3 moles.

x = 1.5 moles.

The initial amount of $\rm SO_3$ = 12 moles

At equilibrium, there has been a 2x reduction.

The amount of $\rm SO_3$ = 12 - 2x

= 12 - 3

= 9 moles.

The amount of $\rm SO_2$ at equilibrium is 2x

= 3 moles.

The amount of $\rm O_2$ at equilibrium is x.

= 1.5 moles.

k can be calculated as: $\rm \dfrac{[SO_2]^2\;[O_2]}{[SO_3]^2}$

k = $\rm \dfrac{[3\;moles/\;3\;L]^2\;[1.5\;moles\;/\;3\;L]}{[9\;moles\;/3\;L]^2}$

k = 0.055.

The value of k for the reaction is 0.055.

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Answer from: Quest

the number of protons in the nucleus of a given element. has slight luster and conducts electricity at high temperatures like metal.but like a nonmetal,boron is brittle and does not conduct electricity well at low temperatures. in graphite, carbon is a soft,brittle solid.it is reflective,ductile,or malleable.

Answer from: Quest

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.