The reaction is: Fe2O3 (s) + 2Al (s) → 2Fe (l) + Al2O3 (s) What mass, in grams, of iron (III) oxide reacted to produce 4.5 mol of Al2O3 ???

718.6 gm

Explanation:

The reaction is: Fe2O3 (s) + 2Al (s) → 2Fe (l) + Al2O3 (s)

What mass, in grams, of iron (III) oxide reacted to produce 4.5 mol of Al2O3

1 mole of Fe2Os produces 1 mol of Al2O3

so 4.5 mols Fe2O3 would produce 4.5 mols Al2O3

the molecular mass of Fe2O3 is

(2 X 55.85) + (16 X 3) =

111.7 + 48 =

159.7

4.5 mols Fe2O6 weighs

4.5 X 159.7 =

718.6 gm

check:

718.6 gm of Fe3O2