If the [OH1-] of a solution at 25oC is 5.8x10^(-5) mol/L, calculate the [H1+] in mol/L, the pH, and the pOH.

1. [H⁺] = 1.58×10¯¹⁰ mol/L

2. pH = 9.8

3. pOH = 4.2

Explanation:

We'll begin by calculating the pOH of the solution. This can be obtained as follow:

Concentration of Hydroxide ion [OH¯] = 5.8×10¯⁵ mol/L

pOH =?

pOH = –Log [OH¯]

pOH = –Log 5.8×10¯⁵

pOH = 4.2

Next, we shall determine the pH of the solution. This can be obtained as follow:

pOH = 4.2

pH =?

pH + pOH = 14

pH + 4.2 = 14

Collect like terms

pH = 14 – 4.2

pH = 9.8

Finally, we shall determine the concentration of Hydrogen ion [H⁺] in the solution. This can be obtained as follow:

pH = 9.8

Concentration of Hydrogen ion [H⁺] =?

pH = –Log [H⁺]

9.8 = –Log [H⁺]

Multiply through by –1

–9.8 = Log [H⁺]

Take the anti log of –9.8

[H⁺] = antilog (–9.8)

[H⁺] = 1.58×10¯¹⁰ mol/L

SUMMARY:

1. [H⁺] = 1.58×10¯¹⁰ mol/L

2. pH = 9.8

3. pOH = 4.2

the maximum mass of nh3 is nh3 in grams

alchemy hadn't scientific methods of study, appeal to mysticism and fantasy, the knowledge of chemistry and physics were modest at that time.

alchemy was - but as new rules were discovered it either changed into chemistry or it became "unscientific".