Aforce is applied to a block sliding along a surface (figure 2). the magnitude of the force is 15 n , and the horizontal component of the force is 4.5 n . at what angle (in degrees) above the horizontal is the force directed?

Thus, the force is directed 72.5° above the horizontal.

Explanation:

The magnitude of the force, F = 15 N

let this force be detected at angle θ from the horizontal, then horizontal component of force is: F cos θ

and vertical component is F sin θ

Horizontal component is given,

F cos θ = 4.5 N

⇒15 N cos θ = 4.5 N

⇒ cos θ = 0.3

⇒ θ = cos⁻¹ 0.3 = 72.5°

answer would be d.) i hope this

explanation:

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