During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What was the volume of O2 used during the experiment?
30 2+ 4A1 -- 2AI2O3
8.70 liters
9.22 liters
10.13 liters
12.81 liters

8.70 liters

Explanation:

First we convert 36.12 g of AI₂O₃ into moles, using its molar mass:

Then we convert AI₂O₃ moles into O₂ moles, using the stoichiometric coefficients of the reaction:

We can now use the PV=nRT equation to calculate the volume, V:

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

4d^55s^1 ( third choice)