45.5 g of ice is heated from -25 degrees celsius to 150 degrees celcius. Calculate the total amount of heat required for the entire process

Q = 16163.88 Joules

Explanation:

Given the following data;

Initial temperature, T1 = -25°C

Final temperature, T2 = 150°C

Mass = 45.5 g

Specific heat capacity of ice = 2.03 J/g°C

To find the quantity of heat required;

Heat capacity is given by the formula;

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 150 - (-25)

dt = 150 + 25

dt = 175°C

Substituting into the formula, we have;

Q = 16163.88 Joules