Using the relationship given in part 1, calculate Ecell if [Cu2+] = 1.453 M and [Cr3+] = 0.00176 M, assuming that the temperature remains at 25°C. Give your answer to two places after the decimal.

1.05 V

Explanation:

Now recall Nernst equation;

Ecell= E°cell - 0.0592/n log [Red]/[Ox]

Now we look at the values of E°cathode and E°anode

E°cathode= 0.34 V

E°anode = -0.74 V

E°cell= 0.34-(-0.74)

E°cell= 1.08 V

[Red] = 1.453 M

[Ox] = 0.00176 M

n= 6

Ecell= E°cell - 0.0592/n log [Red]/[Ox]

Ecell= 1.08 - 0.0592/6 × log[1.453]/[0.00176]

Ecell= 1.08 - 0.0592/6 × 2.917

Ecell= 1.08 - 0.02878

Ecell= 1.05 V

i'm assuming that it's c.) red bank..

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.