How many grams of H2O2 will be produced if 14.86-grams of water is reacted with excess oxygen? How many molecules of H2O2 were produced? 2H2O (l) + O2 (g) ® 2H2O2 (aq)

4.99 ×10²³ molecules

Mass = 28.22 g

Explanation:

Given data:

Mass of H₂O₂ produced = ?

Mass of water react = 14.86 g

Number of molecules of H₂O₂ produced = ?

Solution:

Chemical equation:

2H₂O + O₂        →     2H₂O₂

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 14.86 g/ 18 g/mol

Number of moles = 0.83 mol

Now we will compare the moles of water and H₂O₂.

                   H₂O          :               H₂O₂

                    2              :                2

                  0.83           :             0.83

Mass of H₂O₂:

Mass = number of moles × molar mass

Mass = 0.83 mol × 34 g/mol

Mass = 28.22 g

Number of molecules:

1 mole = 6.022×10²³ molecules

0.83 mol × 6.022×10²³ molecules / 1 mol

4.99 ×10²³ molecules

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