A complex absorbs photons with an energy of 4.10×10^−19 J. What is the wavelength of these photons? If this is the only place in the visible spectrum where the complex absorbs light, what color would you expect the complex to be?

483 nm corresponds to blue light hence the complex will appear orange.

Explanation:

Using the formula;

E= hc/λ

Where;

E = energy of the photon

h = Plank's constant (6.6*10^-34Js)

c = Speed of light (3*10^8 ms-1)

λ = wavelength

λ = hc/E

λ = 6.6*10^-34 * 3*10^8/4.10×10^−19

λ = 4.83 * 10^-7 or 483 nm

483 nm corresponds to blue light

Using the colour wheel approach, if a complex absorbs blue light, then it will appear orange.

c. electrical charges of ionic bonds.