Calculate the concentration, in units of dm-3, of sulfuric acid, H2SO4, which has a solubility of 2 mol dm-3. [Relative atomic mass: H = 1, O = 16, S = 32]

196 gdm-3

Explanation:

There are two major units of concentration, moldm-3 and gdm-3. The first unit refers to molar concentration while the second unit refers to mass concentration. Both units are useful in chemistry when describing the concentration of solutions as deemed expedient in each particular case.

Here we are required to compute the mass concentration from the molar concentration. We must recall that; mass concentration= molar concentration × molar mass

Let us first obtain the molar mass of H2SO4 from the relative atomic masses given=

2(1) + 32 + 4(16) = 98 gmol-1

Molar concentration of H2SO4 = 2 moldm-3

Mass concentration= 2 moldm-3 × 98 gmol-1

Mass concentration = 196 gdm-3

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3