(6 pts.) How many liters of 2.50% m/v NaCl solution will be needed in order to contain 858 g of
NaCl? Show calculation with conversion factors.

34.32 liters

Explanation:

34.32 liters of 2.5% m/v NaCl solution will be needed in order to contain 858 g of NaCl.

2.5% m/v NaCl solution contains 2.5 g of NaCl in 100 mL of solution. It thus means that 100 mL has 2.5 g of NaCl.

If 100 mL solution contains 2.5 g NaCl, then, how many mL will contain 858 g?

= 100 x 858/2.5 = 34, 320 mL

Now, convert 34,320 mL to liters

1 mL = 0.001 Liters

34,320 mL = 34,320 x 0.001 L

   = 34.32 liters.

answer: c.

explanation:

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.