In an oxidation-reduction reaction, the reducing agent In an oxidation-reduction reaction, the reducing agent gains electrons and loses potential energy. loses electrons and loses potential energy. gains electrons and gains potential energy. loses electrons and gains potential energy.

loses electrons and loses potential energy.

Explanation:

A reducing agent looses electrons in an oxidation-reduction reaction. Oxidation is defined as the loss of electrons.

Reducing agents are oxidized in an oxidation-reduction reaction. When a specie looses electrons, it also looses energy. Hence the answer given above.

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml