Examine the following systems of equations: Which three systems do you think would be the easiest
to solve? Why?
y = 4
A
E
Sy=-3x - 5
y = 4x + 30
3x + 4y = 10
x = 2y
F{ y = 3x - 2
x = 3y - 4
y = -2x +8
2x + y = 47
w
Which three systems do you think would be the most
difficult to solve? Why?
y = -2x + 5
{= 3x +7
K
x = -2y + 56
2x + 3y = 31
by = -3x + 10
y = -2x + 6
H
{ x = 2y - 15'(x+y = 10
' = -2x { x=2+1

answer is : muchas/tipicas

have a nice day!

~recklesschicken

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

a is the right answer

step-by-step explanation: