A certain gas is present in a 15.0 L cylinder at 2.0 atm pressure. If the pressure is increased to 4.0 atm the volume of the gas decreases to 7.5 L . Find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys Boyle’s law by entering the numerical values for ki and kf in the space provided. Express your answers to two significant figures separated by a comma.

Ki = 30atmL

Kf = 30atmL

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 15.0L

P1 (initial pressure) = 2atm

V2 (final volume) = 7.5L

P2 (final pressure) = 4atm

Ki (initial constant) =?

Kf (final constant) =?

Boyle's law states that PV = K

Ki = P1V1

Ki = 2 x 15 = 30atmL

Kf = P2V2

Kf = 4 x 7.5 = 30atmL

Since Ki and Kf are the same, the gas obey Boyle's law

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.