An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standard enthalpy of combustion of the fuel is − 26.5kJ/g. Calculate the maximum power (in units of kilowatts) that can be produced by this spacecraft. 1kW = 1kJ/s?

Explanation:

First, we will calculate fuel consumption is as follows.

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    =

                    = kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is kW.

answer; i believe the correct answer is (solid gold);

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.